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Appendix 1: Governing equations

For (h/a) <<1, and assuming that inertia is negligible, one can show [4,7] that for an Oldroyd-B fluid, the dimensionless equations (after eliminating pressure) for axisymmetric flow in cylindrical coordinates are as follows:

Continuity equation  
 \begin{displaymath}
\frac{\partial u}{\partial r}+\frac{u}{r}+\frac{\partial w}{\partial z}=0.

\end{displaymath} (184)

Momentum equations

 
 \begin{displaymath}
(1-\beta)\frac{\partial^{3} u}{\partial z^{3}}+\frac{\partia...
 ...\Sigma}{\partial z}-\frac{\partial \Delta}
{\partial z})=0,

\end{displaymath} (185)
 
 \begin{displaymath}
(1-\beta)\frac{\partial^{2} v}{\partial z^{2}}+\frac{\partia...
 ...artial r}+\frac{2}{r}\zeta+\frac{\partial\Pi}{\partial z}=0.

\end{displaymath} (186)

Constitutive equations

 
 \begin{displaymath}
{\rm De}{\partial\Sigma\over\partial t}+
\Sigma =-{\rm De} [...
 ...ial u}{\partial r}
-2\gamma \frac{\partial u}{\partial z}],

\end{displaymath} (187)

\begin{eqnarray}
{\rm De}{\partial\zeta\over\partial t}+
\zeta &= & - {\rm De} [...
 ...}{\partial z}-\gamma \frac{\partial v}{\partial z} ],
 \nonumber
\end{eqnarray}

   \begin{eqnarray}
{\rm De}{\partial\gamma\over\partial t}+
\gamma &=& - {\rm De} ...
 ... {\partial r}] + \beta \frac{\partial u}{\partial z}, \nonumber

\end{eqnarray}

   \begin{eqnarray}
{\rm De}{\partial\Delta\over\partial t}+
\Delta &=& -{\rm De} [...
 ...frac{u}{r}\Delta-2\Pi \frac{\partial v}{\partial z}], \nonumber

\end{eqnarray}

   \begin{eqnarray}
{\rm De}{\partial\Pi\over\partial t}+
\Pi &=& -{\rm De} [u\frac...
 ...\partial r}]
+\beta \frac{\partial v}{\partial z},
 \nonumber

\end{eqnarray}

   \begin{eqnarray}
{\rm De}{\partial\Gamma\over\partial t}+
\Gamma & =& -{\rm De} ...
 ... z} ]\\ 
 & & +2\beta \frac{\partial w}{\partial z}. \nonumber

\end{eqnarray}

Boundary conditions  
 \begin{displaymath}
u=w=0, \hspace{.2in}v=0 \hspace{.2in} \mbox{on} \hspace{.2in} z=0,

\end{displaymath} (188)
 
 \begin{displaymath}
u=w=0, \hspace{.2in} v=r, \hspace{.2in} \mbox{on} \hspace{.1in} z=1.

\end{displaymath} (189)
For this model the domain is taken to be the infinite region $r \ge 0$.



Michael Renardy
1998-07-13